6z^2+1=2z^2

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Solution for 6z^2+1=2z^2 equation: 



6z^2+1=2z^2

We move all terms to the left:

6z^2+1-(2z^2)=0

We add all the numbers together, and all the variables

4z^2+1=0

a = 4; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·4·1
Δ = -16
Delta is less than zero, so there is no solution for the equation

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